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243122343311 is a prime number
BaseRepresentation
bin1110001001101100111…
…0001000110110001111
3212020112121120200210202
43202123032020312033
512440403304441221
6303404443324115
723364540551351
oct3423316106617
9766477520722
10243122343311
1194120251a61
123b15122063b
1319c07220653
14baa52210d1
1564ce119d0b
hex389b388d8f

243122343311 has 2 divisors, whose sum is σ = 243122343312. Its totient is φ = 243122343310.

The previous prime is 243122343263. The next prime is 243122343313. The reversal of 243122343311 is 113343221342.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 243122343311 - 214 = 243122326927 is a prime.

Together with 243122343313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243122343313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121561171655 + 121561171656.

It is an arithmetic number, because the mean of its divisors is an integer number (121561171656).

Almost surely, 2243122343311 is an apocalyptic number.

243122343311 is a deficient number, since it is larger than the sum of its proper divisors (1).

243122343311 is an equidigital number, since it uses as much as digits as its factorization.

243122343311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368, while the sum is 29.

Adding to 243122343311 its reverse (113343221342), we get a palindrome (356465564653).

The spelling of 243122343311 in words is "two hundred forty-three billion, one hundred twenty-two million, three hundred forty-three thousand, three hundred eleven".