Base | Representation |
---|---|
bin | 1011000011100101011011… |
… | …11000101001100100001000 |
3 | 10012002020122012110122011111 |
4 | 11201302231320221210020 |
5 | 11141313330121012130 |
6 | 123412551022340104 |
7 | 5056341506654251 |
oct | 541625570514410 |
9 | 105066565418144 |
10 | 24312432204040 |
11 | 78239321788a2 |
12 | 2887ab442a634 |
13 | 107486377b406 |
14 | 600a298a5b28 |
15 | 2c264eb9602a |
hex | 161cade29908 |
24312432204040 has 32 divisors (see below), whose sum is σ = 54779054544000. Its totient is φ = 9711447177664.
The previous prime is 24312432204013. The next prime is 24312432204121. The reversal of 24312432204040 is 4040223421342.
It is a junction number, because it is equal to n+sod(n) for n = 24312432203993 and 24312432204011.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 422649130 + ... + 422706649.
It is an arithmetic number, because the mean of its divisors is an integer number (1711845454500).
Almost surely, 224312432204040 is an apocalyptic number.
24312432204040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
24312432204040 is an abundant number, since it is smaller than the sum of its proper divisors (30466622339960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
24312432204040 is a wasteful number, since it uses less digits than its factorization.
24312432204040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 845356509 (or 845356505 counting only the distinct ones).
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 24312432204040 its reverse (4040223421342), we get a palindrome (28352655625382).
The spelling of 24312432204040 in words is "twenty-four trillion, three hundred twelve billion, four hundred thirty-two million, two hundred four thousand, forty".
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