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243130131983 is a prime number
BaseRepresentation
bin1110001001101110101…
…1110110011000001111
3212020120011020101212002
43202123223312120033
512440412303210413
6303405322302515
723364664011014
oct3423353663017
9766504211762
10243130131983
1194124691782
123b153957a3b
1319c08a1982b
14baa628b70b
1564ceb57958
hex389baf660f

243130131983 has 2 divisors, whose sum is σ = 243130131984. Its totient is φ = 243130131982.

The previous prime is 243130131971. The next prime is 243130131997. The reversal of 243130131983 is 389131031342.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 243130131983 - 210 = 243130130959 is a prime.

It is a super-2 number, since 2×2431301319832 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243130131583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565065991 + 121565065992.

It is an arithmetic number, because the mean of its divisors is an integer number (121565065992).

Almost surely, 2243130131983 is an apocalyptic number.

243130131983 is a deficient number, since it is larger than the sum of its proper divisors (1).

243130131983 is an equidigital number, since it uses as much as digits as its factorization.

243130131983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 38.

The spelling of 243130131983 in words is "two hundred forty-three billion, one hundred thirty million, one hundred thirty-one thousand, nine hundred eighty-three".