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243130132151 is a prime number
BaseRepresentation
bin1110001001101110101…
…1110110011010110111
3212020120011020102002022
43202123223312122313
512440412303212101
6303405322303355
723364664011344
oct3423353663267
9766504212068
10243130132151
1194124691915
123b153957b5b
1319c08a1992a
14baa628b7cb
1564ceb57a1b
hex389baf66b7

243130132151 has 2 divisors, whose sum is σ = 243130132152. Its totient is φ = 243130132150.

The previous prime is 243130132039. The next prime is 243130132163. The reversal of 243130132151 is 151231031342.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-243130132151 is a prime.

It is a super-2 number, since 2×2431301321512 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 243130132151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243130132171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565066075 + 121565066076.

It is an arithmetic number, because the mean of its divisors is an integer number (121565066076).

Almost surely, 2243130132151 is an apocalyptic number.

243130132151 is a deficient number, since it is larger than the sum of its proper divisors (1).

243130132151 is an equidigital number, since it uses as much as digits as its factorization.

243130132151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 243130132151 its reverse (151231031342), we get a palindrome (394361163493).

The spelling of 243130132151 in words is "two hundred forty-three billion, one hundred thirty million, one hundred thirty-two thousand, one hundred fifty-one".