Base | Representation |
---|---|
bin | 1110001001101110111… |
… | …1010110110011110111 |
3 | 212020120012222002212012 |
4 | 3202123233112303313 |
5 | 12440413022120010 |
6 | 303405354114435 |
7 | 23365004560061 |
oct | 3423357266367 |
9 | 766505862765 |
10 | 243131051255 |
11 | 9412515a404 |
12 | 3b15411ba1b |
13 | 19c08c7c091 |
14 | baa644a731 |
15 | 64cec8a005 |
hex | 389bbd6cf7 |
243131051255 has 4 divisors (see below), whose sum is σ = 291757261512. Its totient is φ = 194504841000.
The previous prime is 243131051209. The next prime is 243131051257. The reversal of 243131051255 is 552150131342.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 243131051255 - 234 = 225951182071 is a prime.
It is a super-2 number, since 2×2431310512552 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (243131051257) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24313105121 + ... + 24313105130.
It is an arithmetic number, because the mean of its divisors is an integer number (72939315378).
Almost surely, 2243131051255 is an apocalyptic number.
243131051255 is a deficient number, since it is larger than the sum of its proper divisors (48626210257).
243131051255 is an equidigital number, since it uses as much as digits as its factorization.
243131051255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48626210256.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 243131051255 its reverse (552150131342), we get a palindrome (795281182597).
The spelling of 243131051255 in words is "two hundred forty-three billion, one hundred thirty-one million, fifty-one thousand, two hundred fifty-five".
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