Base | Representation |
---|---|
bin | 1110001001101111000… |
… | …0110110001101011101 |
3 | 212020120020200221212201 |
4 | 3202123300312031131 |
5 | 12440413122121023 |
6 | 303405410331501 |
7 | 23365011105235 |
oct | 3423360661535 |
9 | 766506627781 |
10 | 243131442013 |
11 | 941253a6a49 |
12 | 3b154289b91 |
13 | 19c09087bb5 |
14 | baa650ccc5 |
15 | 64ced15bad |
hex | 389bc3635d |
243131442013 has 2 divisors, whose sum is σ = 243131442014. Its totient is φ = 243131442012.
The previous prime is 243131441999. The next prime is 243131442067. The reversal of 243131442013 is 310244131342.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 161396634564 + 81734807449 = 401742^2 + 285893^2 .
It is a cyclic number.
It is not a de Polignac number, because 243131442013 - 217 = 243131310941 is a prime.
It is a super-2 number, since 2×2431314420132 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (243131442613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565721006 + 121565721007.
It is an arithmetic number, because the mean of its divisors is an integer number (121565721007).
Almost surely, 2243131442013 is an apocalyptic number.
It is an amenable number.
243131442013 is a deficient number, since it is larger than the sum of its proper divisors (1).
243131442013 is an equidigital number, since it uses as much as digits as its factorization.
243131442013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 243131442013 its reverse (310244131342), we get a palindrome (553375573355).
The spelling of 243131442013 in words is "two hundred forty-three billion, one hundred thirty-one million, four hundred forty-two thousand, thirteen".
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