Base | Representation |
---|---|
bin | 1110001001110001011… |
… | …0111111011001101011 |
3 | 212020120221111222002102 |
4 | 3202130112333121223 |
5 | 12440423202104011 |
6 | 303410404524015 |
7 | 23365162102211 |
oct | 3423426773153 |
9 | 766527458072 |
10 | 243141441131 |
11 | 94130006486 |
12 | 3b1576b060b |
13 | 19c0b179234 |
14 | baa7992cb1 |
15 | 64d0b3d73b |
hex | 389c5bf66b |
243141441131 has 2 divisors, whose sum is σ = 243141441132. Its totient is φ = 243141441130.
The previous prime is 243141441079. The next prime is 243141441157. The reversal of 243141441131 is 131144141342.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-243141441131 is a prime.
It is a super-2 number, since 2×2431414411312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 243141441094 and 243141441103.
It is not a weakly prime, because it can be changed into another prime (243141441931) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121570720565 + 121570720566.
It is an arithmetic number, because the mean of its divisors is an integer number (121570720566).
Almost surely, 2243141441131 is an apocalyptic number.
243141441131 is a deficient number, since it is larger than the sum of its proper divisors (1).
243141441131 is an equidigital number, since it uses as much as digits as its factorization.
243141441131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4608, while the sum is 29.
Adding to 243141441131 its reverse (131144141342), we get a palindrome (374285582473).
The spelling of 243141441131 in words is "two hundred forty-three billion, one hundred forty-one million, four hundred forty-one thousand, one hundred thirty-one".
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