Base | Representation |
---|---|
bin | 1110001010001011101… |
… | …0001000000110101101 |
3 | 212020212121021010212022 |
4 | 3202202322020012231 |
5 | 12441134314040432 |
6 | 303425331515525 |
7 | 23400665030426 |
oct | 3424272100655 |
9 | 766777233768 |
10 | 243251315117 |
11 | 94187031428 |
12 | 3b188458ba5 |
13 | 19c27b69125 |
14 | bab83d464d |
15 | 64da5e3b12 |
hex | 38a2e881ad |
243251315117 has 2 divisors, whose sum is σ = 243251315118. Its totient is φ = 243251315116.
The previous prime is 243251315101. The next prime is 243251315137. The reversal of 243251315117 is 711513152342.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 212349542596 + 30901772521 = 460814^2 + 175789^2 .
It is a cyclic number.
It is not a de Polignac number, because 243251315117 - 24 = 243251315101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (243251315137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121625657558 + 121625657559.
It is an arithmetic number, because the mean of its divisors is an integer number (121625657559).
Almost surely, 2243251315117 is an apocalyptic number.
It is an amenable number.
243251315117 is a deficient number, since it is larger than the sum of its proper divisors (1).
243251315117 is an equidigital number, since it uses as much as digits as its factorization.
243251315117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25200, while the sum is 35.
Adding to 243251315117 its reverse (711513152342), we get a palindrome (954764467459).
The spelling of 243251315117 in words is "two hundred forty-three billion, two hundred fifty-one million, three hundred fifteen thousand, one hundred seventeen".
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