Base | Representation |
---|---|
bin | 10110101010111010… |
… | …111110111000011101 |
3 | 2022211110120022122122 |
4 | 112222322332320131 |
5 | 344323130100432 |
6 | 15103250352325 |
7 | 1521141125303 |
oct | 265272767035 |
9 | 68743508578 |
10 | 24342425117 |
11 | a36173430a |
12 | 487428b6a5 |
13 | 23ac22c75a |
14 | 126ccd4273 |
15 | 9770d0612 |
hex | 5aaebee1d |
24342425117 has 2 divisors, whose sum is σ = 24342425118. Its totient is φ = 24342425116.
The previous prime is 24342425071. The next prime is 24342425119. The reversal of 24342425117 is 71152424342.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23907035161 + 435389956 = 154619^2 + 20866^2 .
It is a cyclic number.
It is not a de Polignac number, because 24342425117 - 28 = 24342424861 is a prime.
Together with 24342425119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24342425119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12171212558 + 12171212559.
It is an arithmetic number, because the mean of its divisors is an integer number (12171212559).
Almost surely, 224342425117 is an apocalyptic number.
It is an amenable number.
24342425117 is a deficient number, since it is larger than the sum of its proper divisors (1).
24342425117 is an equidigital number, since it uses as much as digits as its factorization.
24342425117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 53760, while the sum is 35.
Adding to 24342425117 its reverse (71152424342), we get a palindrome (95494849459).
The spelling of 24342425117 in words is "twenty-four billion, three hundred forty-two million, four hundred twenty-five thousand, one hundred seventeen".
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