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2434325113 = 11221302283
BaseRepresentation
bin1001000100011000…
…1101101001111001
320021122121112021101
42101012031221321
514441141400423
61041320011401
7114216264523
oct22106155171
96248545241
102434325113
11103a127540
1257b300b61
132ca44647c
14191436a13
15e3aa67ad
hex9118da79

2434325113 has 4 divisors (see below), whose sum is σ = 2655627408. Its totient is φ = 2213022820.

The previous prime is 2434325111. The next prime is 2434325123. The reversal of 2434325113 is 3115234342.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2434325113 - 21 = 2434325111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2434325111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110651131 + ... + 110651152.

It is an arithmetic number, because the mean of its divisors is an integer number (663906852).

Almost surely, 22434325113 is an apocalyptic number.

It is an amenable number.

2434325113 is a deficient number, since it is larger than the sum of its proper divisors (221302295).

2434325113 is a wasteful number, since it uses less digits than its factorization.

2434325113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221302294.

The product of its digits is 8640, while the sum is 28.

The square root of 2434325113 is about 49338.8803379242. The cubic root of 2434325113 is about 1345.2185883176.

Adding to 2434325113 its reverse (3115234342), we get a palindrome (5549559455).

The spelling of 2434325113 in words is "two billion, four hundred thirty-four million, three hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 11 221302283 2434325113