Base | Representation |
---|---|
bin | 110111011111011110111111… |
… | …110101011111100111010111 |
3 | 1012000010112120101012222210001 |
4 | 313133132333311133213113 |
5 | 223442103441123210431 |
6 | 2223021502324512131 |
7 | 102256321535212063 |
oct | 6737367765374727 |
9 | 1160115511188701 |
10 | 244056145131991 |
11 | 708446a243a715 |
12 | 2345787124b647 |
13 | a62451b573a5a |
14 | 443a547d5aaa3 |
15 | 1d336d8d60e61 |
hex | ddf7bfd5f9d7 |
244056145131991 has 2 divisors, whose sum is σ = 244056145131992. Its totient is φ = 244056145131990.
The previous prime is 244056145131973. The next prime is 244056145132103. The reversal of 244056145131991 is 199131541650442.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 244056145131991 - 25 = 244056145131959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (244056145131961) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (37) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122028072565995 + 122028072565996.
It is an arithmetic number, because the mean of its divisors is an integer number (122028072565996).
Almost surely, 2244056145131991 is an apocalyptic number.
244056145131991 is a deficient number, since it is larger than the sum of its proper divisors (1).
244056145131991 is an equidigital number, since it uses as much as digits as its factorization.
244056145131991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4665600, while the sum is 55.
The spelling of 244056145131991 in words is "two hundred forty-four trillion, fifty-six billion, one hundred forty-five million, one hundred thirty-one thousand, nine hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •