Base | Representation |
---|---|
bin | 1110001101011101111… |
… | …0101110100101001101 |
3 | 212100011001220220010221 |
4 | 3203113132232211031 |
5 | 12444441112401013 |
6 | 304053040231341 |
7 | 23431565011255 |
oct | 3432736564515 |
9 | 770131826127 |
10 | 244133325133 |
11 | 94599996625 |
12 | 3b39390b551 |
13 | 1a038804249 |
14 | bb5d5ca965 |
15 | 653cc6a08d |
hex | 38d77ae94d |
244133325133 has 2 divisors, whose sum is σ = 244133325134. Its totient is φ = 244133325132.
The previous prime is 244133325113. The next prime is 244133325151. The reversal of 244133325133 is 331523331442.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 229324138884 + 14809186249 = 478878^2 + 121693^2 .
It is a cyclic number.
It is not a de Polignac number, because 244133325133 - 229 = 243596454221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (244133325113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122066662566 + 122066662567.
It is an arithmetic number, because the mean of its divisors is an integer number (122066662567).
Almost surely, 2244133325133 is an apocalyptic number.
It is an amenable number.
244133325133 is a deficient number, since it is larger than the sum of its proper divisors (1).
244133325133 is an equidigital number, since it uses as much as digits as its factorization.
244133325133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 77760, while the sum is 34.
Adding to 244133325133 its reverse (331523331442), we get a palindrome (575656656575).
The spelling of 244133325133 in words is "two hundred forty-four billion, one hundred thirty-three million, three hundred twenty-five thousand, one hundred thirty-three".
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