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244153132117 is a prime number
BaseRepresentation
bin1110001101100010101…
…0010010010001010101
3212100012110012012012221
43203120222102101111
513000011200211432
6304055024542341
723432225244466
oct3433052222125
9770173165187
10244153132117
11945aa094934
123b39a4819b1
131a03c94a85b
14bb620a4d6d
15653e87db97
hex38d8a92455

244153132117 has 2 divisors, whose sum is σ = 244153132118. Its totient is φ = 244153132116.

The previous prime is 244153132049. The next prime is 244153132121. The reversal of 244153132117 is 711231351442.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 183144626116 + 61008506001 = 427954^2 + 246999^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-244153132117 is a prime.

It is a super-2 number, since 2×2441531321172 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (244153132127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122076566058 + 122076566059.

It is an arithmetic number, because the mean of its divisors is an integer number (122076566059).

Almost surely, 2244153132117 is an apocalyptic number.

It is an amenable number.

244153132117 is a deficient number, since it is larger than the sum of its proper divisors (1).

244153132117 is an equidigital number, since it uses as much as digits as its factorization.

244153132117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20160, while the sum is 34.

Adding to 244153132117 its reverse (711231351442), we get a palindrome (955384483559).

The spelling of 244153132117 in words is "two hundred forty-four billion, one hundred fifty-three million, one hundred thirty-two thousand, one hundred seventeen".