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244155300047 is a prime number
BaseRepresentation
bin1110001101100011001…
…0100011100011001111
3212100012121021100001122
43203120302203203033
513000012224100142
6304055143231155
723432252544131
oct3433062434317
9770177240048
10244155300047
119460033570a
123b39b1484bb
131a040229559
14bb624ab051
15653eb5b1d2
hex38d8ca38cf

244155300047 has 2 divisors, whose sum is σ = 244155300048. Its totient is φ = 244155300046.

The previous prime is 244155300017. The next prime is 244155300049. The reversal of 244155300047 is 740003551442.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 244155300047 - 210 = 244155299023 is a prime.

It is a super-2 number, since 2×2441553000472 (a number of 24 digits) contains 22 as substring.

Together with 244155300049, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (244155300049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122077650023 + 122077650024.

It is an arithmetic number, because the mean of its divisors is an integer number (122077650024).

Almost surely, 2244155300047 is an apocalyptic number.

244155300047 is a deficient number, since it is larger than the sum of its proper divisors (1).

244155300047 is an equidigital number, since it uses as much as digits as its factorization.

244155300047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 67200, while the sum is 35.

Adding to 244155300047 its reverse (740003551442), we get a palindrome (984158851489).

The spelling of 244155300047 in words is "two hundred forty-four billion, one hundred fifty-five million, three hundred thousand, forty-seven".