Base | Representation |
---|---|
bin | 1110001101100011001… |
… | …0100011100011001111 |
3 | 212100012121021100001122 |
4 | 3203120302203203033 |
5 | 13000012224100142 |
6 | 304055143231155 |
7 | 23432252544131 |
oct | 3433062434317 |
9 | 770177240048 |
10 | 244155300047 |
11 | 9460033570a |
12 | 3b39b1484bb |
13 | 1a040229559 |
14 | bb624ab051 |
15 | 653eb5b1d2 |
hex | 38d8ca38cf |
244155300047 has 2 divisors, whose sum is σ = 244155300048. Its totient is φ = 244155300046.
The previous prime is 244155300017. The next prime is 244155300049. The reversal of 244155300047 is 740003551442.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 244155300047 - 210 = 244155299023 is a prime.
It is a super-2 number, since 2×2441553000472 (a number of 24 digits) contains 22 as substring.
Together with 244155300049, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (244155300049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122077650023 + 122077650024.
It is an arithmetic number, because the mean of its divisors is an integer number (122077650024).
Almost surely, 2244155300047 is an apocalyptic number.
244155300047 is a deficient number, since it is larger than the sum of its proper divisors (1).
244155300047 is an equidigital number, since it uses as much as digits as its factorization.
244155300047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67200, while the sum is 35.
Adding to 244155300047 its reverse (740003551442), we get a palindrome (984158851489).
The spelling of 244155300047 in words is "two hundred forty-four billion, one hundred fifty-five million, three hundred thousand, forty-seven".
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