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244233093941 is a prime number
BaseRepresentation
bin1110001101110101101…
…1010100001100110101
3212100102000122200012222
43203131123110030311
513000142133001231
6304111002452125
723434216021364
oct3433533241465
9770360580188
10244233093941
119464023a391
123b401204045
131a053396745
14bb6c95b7db
1565468c627b
hex38dd6d4335

244233093941 has 2 divisors, whose sum is σ = 244233093942. Its totient is φ = 244233093940.

The previous prime is 244233093823. The next prime is 244233093943. The reversal of 244233093941 is 149390332442.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 243532380100 + 700713841 = 493490^2 + 26471^2 .

It is a cyclic number.

It is not a de Polignac number, because 244233093941 - 218 = 244232831797 is a prime.

It is a super-2 number, since 2×2442330939412 (a number of 24 digits) contains 22 as substring.

Together with 244233093943, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 244233093892 and 244233093901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (244233093943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122116546970 + 122116546971.

It is an arithmetic number, because the mean of its divisors is an integer number (122116546971).

Almost surely, 2244233093941 is an apocalyptic number.

It is an amenable number.

244233093941 is a deficient number, since it is larger than the sum of its proper divisors (1).

244233093941 is an equidigital number, since it uses as much as digits as its factorization.

244233093941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 44.

The spelling of 244233093941 in words is "two hundred forty-four billion, two hundred thirty-three million, ninety-three thousand, nine hundred forty-one".