Base | Representation |
---|---|
bin | 1110001110001101110… |
… | …0010010010000011111 |
3 | 212100200001112210222111 |
4 | 3203203130102100133 |
5 | 13000344001331143 |
6 | 304125005454451 |
7 | 23436552554425 |
oct | 3434334222037 |
9 | 770601483874 |
10 | 244334011423 |
11 | 946921a8167 |
12 | 3b42ab71427 |
13 | 1a06b26ba28 |
14 | bb7c10b115 |
15 | 65506ac99d |
hex | 38e371241f |
244334011423 has 2 divisors, whose sum is σ = 244334011424. Its totient is φ = 244334011422.
The previous prime is 244334011421. The next prime is 244334011433. The reversal of 244334011423 is 324110433442.
244334011423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 244334011423 - 21 = 244334011421 is a prime.
Together with 244334011421, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (244334011421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122167005711 + 122167005712.
It is an arithmetic number, because the mean of its divisors is an integer number (122167005712).
Almost surely, 2244334011423 is an apocalyptic number.
244334011423 is a deficient number, since it is larger than the sum of its proper divisors (1).
244334011423 is an equidigital number, since it uses as much as digits as its factorization.
244334011423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 244334011423 its reverse (324110433442), we get a palindrome (568444444865).
The spelling of 244334011423 in words is "two hundred forty-four billion, three hundred thirty-four million, eleven thousand, four hundred twenty-three".
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