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244444420133 is a prime number
BaseRepresentation
bin1110001110101000000…
…1011101100000100101
3212100221202022011020222
43203222001131200211
513001110232421013
6304143552134125
723442363200624
oct3435201354045
9770852264228
10244444420133
1194739558931
123b45bb37345
131a0880b8124
14bb8ca4b6bb
15655a21b508
hex38ea05d825

244444420133 has 2 divisors, whose sum is σ = 244444420134. Its totient is φ = 244444420132.

The previous prime is 244444420093. The next prime is 244444420159. The reversal of 244444420133 is 331024444442.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 244240558849 + 203861284 = 494207^2 + 14278^2 .

It is a cyclic number.

It is not a de Polignac number, because 244444420133 - 216 = 244444354597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 244444420093 and 244444420102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (244444420433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122222210066 + 122222210067.

It is an arithmetic number, because the mean of its divisors is an integer number (122222210067).

Almost surely, 2244444420133 is an apocalyptic number.

It is an amenable number.

244444420133 is a deficient number, since it is larger than the sum of its proper divisors (1).

244444420133 is an equidigital number, since it uses as much as digits as its factorization.

244444420133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 147456, while the sum is 35.

Adding to 244444420133 its reverse (331024444442), we get a palindrome (575468864575).

The spelling of 244444420133 in words is "two hundred forty-four billion, four hundred forty-four million, four hundred twenty thousand, one hundred thirty-three".