245100125440133 has 2 divisors, whose sum is σ = 245100125440134. Its totient is φ = 245100125440132.

The previous prime is 245100125440043. The next prime is 245100125440151. The reversal of 245100125440133 is 331044521001542.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 148156074675844 + 96944050764289 = 12171938^2 + 9846017^2 .

It is a cyclic number.

It is not a de Polignac number, because 245100125440133 - 2¹⁸ = 245100125177989 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 245100125440093 and 245100125440102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (245100125440333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122550062720066 + 122550062720067.

It is an arithmetic number, because the mean of its divisors is an integer number (122550062720067).

Almost surely, 2^{245100125440133} is an apocalyptic number.

It is an amenable number.

245100125440133 is a deficient number, since it is larger than the sum of its proper divisors (1).

245100125440133 is an equidigital number, since it uses as much as digits as its factorization.

245100125440133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 245100125440133 its reverse (331044521001542), we get a palindrome (576144646441675).

The spelling of 245100125440133 in words is "two hundred forty-five trillion, one hundred billion, one hundred twenty-five million, four hundred forty thousand, one hundred thirty-three".