Base | Representation |
---|---|
bin | 110111101110101011010001… |
… | …111010010100100010010111 |
3 | 1012010211100021011100120002022 |
4 | 313232223101322110202113 |
5 | 224111210024103041101 |
6 | 2225141235422003355 |
7 | 102424620411341642 |
oct | 6756532172244227 |
9 | 1163740234316068 |
10 | 245100125440151 |
11 | 7110741a078023 |
12 | 235a606811655b |
13 | a69bac540a477 |
14 | 4474ca343aa59 |
15 | 1d5093b744a1b |
hex | deead1e94897 |
245100125440151 has 2 divisors, whose sum is σ = 245100125440152. Its totient is φ = 245100125440150.
The previous prime is 245100125440133. The next prime is 245100125440171. The reversal of 245100125440151 is 151044521001542.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 245100125440151 - 226 = 245100058331287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (245100125440171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122550062720075 + 122550062720076.
It is an arithmetic number, because the mean of its divisors is an integer number (122550062720076).
Almost surely, 2245100125440151 is an apocalyptic number.
245100125440151 is a deficient number, since it is larger than the sum of its proper divisors (1).
245100125440151 is an equidigital number, since it uses as much as digits as its factorization.
245100125440151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32000, while the sum is 35.
Adding to 245100125440151 its reverse (151044521001542), we get a palindrome (396144646441693).
The spelling of 245100125440151 in words is "two hundred forty-five trillion, one hundred billion, one hundred twenty-five million, four hundred forty thousand, one hundred fifty-one".
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