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245114134312151 = 131031306314013443
BaseRepresentation
bin110111101110111000010100…
…111001111011010011010111
31012010212200102110111222202102
4313232320110321323103113
5224111422221340442101
62225151513452432315
7102425624514651236
oct6756702471732327
91163780373458672
10245114134312151
1171112358785995
12235a891777869b
13a6a0218804640
144475831b82b1d
151d50eab52b86b
hexdeee14e7b4d7

245114134312151 has 16 divisors (see below), whose sum is σ = 266552296797696. Its totient is φ = 224045341190496.

The previous prime is 245114134312141. The next prime is 245114134312183. The reversal of 245114134312151 is 151213431411542.

It is a happy number.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-245114134312151 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (245114134312141) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10484636 + ... + 24498078.

It is an arithmetic number, because the mean of its divisors is an integer number (16659518549856).

Almost surely, 2245114134312151 is an apocalyptic number.

245114134312151 is a deficient number, since it is larger than the sum of its proper divisors (21438162485545).

245114134312151 is a wasteful number, since it uses less digits than its factorization.

245114134312151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14026622.

The product of its digits is 57600, while the sum is 38.

Adding to 245114134312151 its reverse (151213431411542), we get a palindrome (396327565723693).

The spelling of 245114134312151 in words is "two hundred forty-five trillion, one hundred fourteen billion, one hundred thirty-four million, three hundred twelve thousand, one hundred fifty-one".

Divisors: 1 13 103 1339 13063 169819 1345489 14013443 17491357 182174759 1443384629 18764000177 183057605909 2379748876817 18854933408627 245114134312151