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245120313407 is a prime number
BaseRepresentation
bin1110010001001001001…
…1110010100000111111
3212102200212010002112012
43210102103302200333
513004001300012112
6304335015001435
723465211200144
oct3442223624077
9772625102465
10245120313407
1194a56032512
123b60a36927b
131a165136a88
14bc1470c3cb
15659972b022
hex39124f283f

245120313407 has 2 divisors, whose sum is σ = 245120313408. Its totient is φ = 245120313406.

The previous prime is 245120313391. The next prime is 245120313409. The reversal of 245120313407 is 704313021542.

245120313407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 245120313407 - 24 = 245120313391 is a prime.

Together with 245120313409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (245120313409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122560156703 + 122560156704.

It is an arithmetic number, because the mean of its divisors is an integer number (122560156704).

Almost surely, 2245120313407 is an apocalyptic number.

245120313407 is a deficient number, since it is larger than the sum of its proper divisors (1).

245120313407 is an equidigital number, since it uses as much as digits as its factorization.

245120313407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 32.

Adding to 245120313407 its reverse (704313021542), we get a palindrome (949433334949).

The spelling of 245120313407 in words is "two hundred forty-five billion, one hundred twenty million, three hundred thirteen thousand, four hundred seven".