Base | Representation |
---|---|
bin | 100011101100110110100… |
… | …010100001010100001011 |
3 | 22200112111120120022021120 |
4 | 203230312202201110023 |
5 | 310143420341020120 |
6 | 5115014403210323 |
7 | 342151041233400 |
oct | 43546642412413 |
9 | 8615446508246 |
10 | 2453341345035 |
11 | 86650225a209 |
12 | 3375830769a3 |
13 | 14a46cc6c569 |
14 | 86a570422a7 |
15 | 43c3c789140 |
hex | 23b368a150b |
2453341345035 has 72 divisors (see below), whose sum is σ = 4729105523376. Its totient is φ = 1082853838080.
The previous prime is 2453341345009. The next prime is 2453341345061. The reversal of 2453341345035 is 5305431433542.
It is an interprime number because it is at equal distance from previous prime (2453341345009) and next prime (2453341345061).
It is not a de Polignac number, because 2453341345035 - 213 = 2453341336843 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 1366336 + ... + 2602605.
It is an arithmetic number, because the mean of its divisors is an integer number (65682021158).
Almost surely, 22453341345035 is an apocalyptic number.
2453341345035 is a deficient number, since it is larger than the sum of its proper divisors (2275764178341).
2453341345035 is a wasteful number, since it uses less digits than its factorization.
2453341345035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3969021 (or 3968985 counting only the distinct ones).
The product of its (nonzero) digits is 1296000, while the sum is 42.
Adding to 2453341345035 its reverse (5305431433542), we get a palindrome (7758772778577).
The spelling of 2453341345035 in words is "two trillion, four hundred fifty-three billion, three hundred forty-one million, three hundred forty-five thousand, thirty-five".
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