248112131 has 2 divisors, whose sum is σ = 248112132. Its totient is φ = 248112130.

The previous prime is 248112113. The next prime is 248112167. The reversal of 248112131 is 131211842.

Together with previous prime (248112113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-248112131 is a prime.

It is a super-2 number, since 2×248112131² = 123119259098722322, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 248112097 and 248112106.

It is not a weakly prime, because it can be changed into another prime (248112191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124056065 + 124056066.

It is an arithmetic number, because the mean of its divisors is an integer number (124056066).

Almost surely, 2^248112131 is an apocalyptic number.

248112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

248112131 is an equidigital number, since it uses as much as digits as its factorization.

248112131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384, while the sum is 23.

The square root of 248112131 is about 15751.5755085007. The cubic root of 248112131 is about 628.3708060371.

Adding to 248112131 its reverse (131211842), we get a palindrome (379323973).

The spelling of 248112131 in words is "two hundred forty-eight million, one hundred twelve thousand, one hundred thirty-one".