2493802741117 has 2 divisors, whose sum is σ = 2493802741118. Its totient is φ = 2493802741116.

The previous prime is 2493802741061. The next prime is 2493802741123. The reversal of 2493802741117 is 7111472083942.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2405442800601 + 88359940516 = 1550949^2 + 297254^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2493802741117 is a prime.

It is a super-2 number, since 2×2493802741117² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2493802741517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1246901370558 + 1246901370559.

It is an arithmetic number, because the mean of its divisors is an integer number (1246901370559).

Almost surely, 2^{2493802741117} is an apocalyptic number.

It is an amenable number.

2493802741117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2493802741117 is an equidigital number, since it uses as much as digits as its factorization.

2493802741117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 677376, while the sum is 49.

The spelling of 2493802741117 in words is "two trillion, four hundred ninety-three billion, eight hundred two million, seven hundred forty-one thousand, one hundred seventeen".