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2493984051543 = 38310016000207
BaseRepresentation
bin100100010010101101000…
…010001001000101010111
322211102102000222201100210
4210102231002021011113
5311330134404122133
65145415341340503
7345120151443165
oct44225502110527
98742360881323
102493984051543
11881768a85156
12343426267733
1315124922111a
14889d0b12235
1544d1a8c7763
hex244ad089157

2493984051543 has 8 divisors (see below), whose sum is σ = 3365376069888. Its totient is φ = 1642624033784.

The previous prime is 2493984051529. The next prime is 2493984051551. The reversal of 2493984051543 is 3451504893942.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2493984051543 - 217 = 2493983920471 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2493984051523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5007999855 + ... + 5008000352.

It is an arithmetic number, because the mean of its divisors is an integer number (420672008736).

Almost surely, 22493984051543 is an apocalyptic number.

2493984051543 is a deficient number, since it is larger than the sum of its proper divisors (871392018345).

2493984051543 is a wasteful number, since it uses less digits than its factorization.

2493984051543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10016000293.

The product of its (nonzero) digits is 18662400, while the sum is 57.

The spelling of 2493984051543 in words is "two trillion, four hundred ninety-three billion, nine hundred eighty-four million, fifty-one thousand, five hundred forty-three".

Divisors: 1 3 83 249 10016000207 30048000621 831328017181 2493984051543