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25000041023 = 105509236947
BaseRepresentation
bin10111010010000111…
…100101101000111111
32101112021222200002022
4113102013211220333
5402200002303043
615252421350355
71543344561656
oct272207455077
971467880068
1025000041023
11a669964931
124a185683bb
13248554c0a9
1412d239819d
159b4bce868
hex5d21e5a3f

25000041023 has 4 divisors (see below), whose sum is σ = 25000383480. Its totient is φ = 24999698568.

The previous prime is 25000040983. The next prime is 25000041041. The reversal of 25000041023 is 32014000052.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 25000041023 - 212 = 25000036927 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25000040992 and 25000041010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25000041823) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12965 + ... + 223982.

It is an arithmetic number, because the mean of its divisors is an integer number (6250095870).

Almost surely, 225000041023 is an apocalyptic number.

25000041023 is a deficient number, since it is larger than the sum of its proper divisors (342457).

25000041023 is a wasteful number, since it uses less digits than its factorization.

25000041023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 342456.

The product of its (nonzero) digits is 240, while the sum is 17.

Adding to 25000041023 its reverse (32014000052), we get a palindrome (57014041075).

The spelling of 25000041023 in words is "twenty-five billion, forty-one thousand, twenty-three".

Divisors: 1 105509 236947 25000041023