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25001235133 = 74595377723
BaseRepresentation
bin10111010010001100…
…001001001010111101
32101112101020100002121
4113102030021022331
5402200304011013
615252503122541
71543360664230
oct272214111275
971471210077
1025001235133
11a66a5aaaa6
124a18a43451
132485879774
1412d25c9417
159b4d6858d
hex5d23092bd

25001235133 has 8 divisors (see below), whose sum is σ = 28573829568. Its totient is φ = 21428888064.

The previous prime is 25001235089. The next prime is 25001235187. The reversal of 25001235133 is 33153210052.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 25001235133 - 233 = 16411300541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25001235098 and 25001235107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25001235433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 282810 + ... + 360532.

It is an arithmetic number, because the mean of its divisors is an integer number (3571728696).

Almost surely, 225001235133 is an apocalyptic number.

It is an amenable number.

25001235133 is a deficient number, since it is larger than the sum of its proper divisors (3572594435).

25001235133 is an equidigital number, since it uses as much as digits as its factorization.

25001235133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123683.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 25001235133 its reverse (33153210052), we get a palindrome (58154445185).

The spelling of 25001235133 in words is "twenty-five billion, one million, two hundred thirty-five thousand, one hundred thirty-three".

Divisors: 1 7 45953 77723 321671 544061 3571605019 25001235133