Base | Representation |
---|---|
bin | 111000110110100110000100… |
… | …111010111011101011010111 |
3 | 1012210022210222200001200212102 |
4 | 320312212010322323223113 |
5 | 230233143203311100120 |
6 | 2243443510555512315 |
7 | 103444651210411466 |
oct | 7066460472735327 |
9 | 1183283880050772 |
10 | 250042341112535 |
11 | 727423a7a70a24 |
12 | 24063a6a15869b |
13 | a969b78aa25aa |
14 | 45a61846ca9dd |
15 | 1dd9295ec8d75 |
hex | e36984ebbad7 |
250042341112535 has 8 divisors (see below), whose sum is σ = 306434869108416. Its totient is φ = 195777833041120.
The previous prime is 250042341112507. The next prime is 250042341112549. The reversal of 250042341112535 is 535211143240052.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 250042341112535 - 214 = 250042341096151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 532004980856 + ... + 532004981325.
It is an arithmetic number, because the mean of its divisors is an integer number (38304358638552).
Almost surely, 2250042341112535 is an apocalyptic number.
250042341112535 is a deficient number, since it is larger than the sum of its proper divisors (56392527995881).
250042341112535 is a wasteful number, since it uses less digits than its factorization.
250042341112535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1064009962233.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 250042341112535 its reverse (535211143240052), we get a palindrome (785253484352587).
The spelling of 250042341112535 in words is "two hundred fifty trillion, forty-two billion, three hundred forty-one million, one hundred twelve thousand, five hundred thirty-five".
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