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250042535125133 = 3129092772735727
BaseRepresentation
bin111000110110100110010000…
…011111000010000010001101
31012210022211111012010120010012
4320312212100133002002031
5230233144102443001013
62243443542130123005
7103444656054451052
oct7066462037020215
91183284435116105
10250042535125133
1172742497534513
1224063b03120465
13a969baa04154a
1445a61a2391029
151dd92a804e1a8
hexe369907c208d

250042535125133 has 8 divisors (see below), whose sum is σ = 258197150991360. Its totient is φ = 241893464736240.

The previous prime is 250042535125109. The next prime is 250042535125211. The reversal of 250042535125133 is 331521535240052.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 250042535125133 - 244 = 232450349080717 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (250042535124133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1386277685 + ... + 1386458042.

It is an arithmetic number, because the mean of its divisors is an integer number (32274643873920).

Almost surely, 2250042535125133 is an apocalyptic number.

It is an amenable number.

250042535125133 is a deficient number, since it is larger than the sum of its proper divisors (8154615866227).

250042535125133 is a wasteful number, since it uses less digits than its factorization.

250042535125133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2772738667.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 250042535125133 in words is "two hundred fifty trillion, forty-two billion, five hundred thirty-five million, one hundred twenty-five thousand, one hundred thirty-three".

Divisors: 1 31 2909 90179 2772735727 85954807537 8065888229843 250042535125133