Base | Representation |
---|---|
bin | 10111010010011110… |
… | …101110110111010001 |
3 | 2101112201101220120100 |
4 | 113102132232313101 |
5 | 402203030424423 |
6 | 15253155403013 |
7 | 1543450261200 |
oct | 272236566721 |
9 | 71481356510 |
10 | 25006108113 |
11 | a672329158 |
12 | 4a1a5b3469 |
13 | 248689479c |
14 | 12d30d7237 |
15 | 9b54cc343 |
hex | 5d27aedd1 |
25006108113 has 72 divisors (see below), whose sum is σ = 42967780128. Its totient is φ = 13969525248.
The previous prime is 25006108109. The next prime is 25006108151. The reversal of 25006108113 is 31180160052.
It is not a de Polignac number, because 25006108113 - 22 = 25006108109 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (25006108513) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 3546970 + ... + 3554012.
It is an arithmetic number, because the mean of its divisors is an integer number (596774724).
Almost surely, 225006108113 is an apocalyptic number.
It is an amenable number.
25006108113 is a deficient number, since it is larger than the sum of its proper divisors (17961672015).
25006108113 is a wasteful number, since it uses less digits than its factorization.
25006108113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7243 (or 7233 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 27.
Adding to 25006108113 its reverse (31180160052), we get a palindrome (56186268165).
The spelling of 25006108113 in words is "twenty-five billion, six million, one hundred eight thousand, one hundred thirteen".
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