Base | Representation |
---|---|
bin | 10111010010100110… |
… | …000100110100011101 |
3 | 2101112212000201002102 |
4 | 113102212010310131 |
5 | 402204024024203 |
6 | 15253304534445 |
7 | 1543502526233 |
oct | 272246046435 |
9 | 71485021072 |
10 | 25008033053 |
11 | a673423413 |
12 | 4a1b181425 |
13 | 24870b99c3 |
14 | 12d3478953 |
15 | 9b575c888 |
hex | 5d2984d1d |
25008033053 has 4 divisors (see below), whose sum is σ = 25431898080. Its totient is φ = 24584168028.
The previous prime is 25008033041. The next prime is 25008033059. The reversal of 25008033053 is 35033080052.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25008033053 - 210 = 25008032029 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25008033059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211932425 + ... + 211932542.
It is an arithmetic number, because the mean of its divisors is an integer number (6357974520).
Almost surely, 225008033053 is an apocalyptic number.
It is an amenable number.
25008033053 is a deficient number, since it is larger than the sum of its proper divisors (423865027).
25008033053 is an equidigital number, since it uses as much as digits as its factorization.
25008033053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 423865026.
The product of its (nonzero) digits is 10800, while the sum is 29.
The spelling of 25008033053 in words is "twenty-five billion, eight million, thirty-three thousand, fifty-three".
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