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2501004131 is a prime number
BaseRepresentation
bin1001010100010010…
…0100101101100011
320110022002011200122
42111010210231203
520110224113011
61052101110455
7115656120143
oct22504445543
96408064618
102501004131
11107382a46a
125996b842b
1330b1c1502
1419a232923
15e98783db
hex95124b63

2501004131 has 2 divisors, whose sum is σ = 2501004132. Its totient is φ = 2501004130.

The previous prime is 2501004119. The next prime is 2501004133. The reversal of 2501004131 is 1314001052.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2501004131 - 214 = 2500987747 is a prime.

It is a super-2 number, since 2×25010041312 = 12510043326558130322, which contains 22 as substring.

Together with 2501004133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2501004133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250502065 + 1250502066.

It is an arithmetic number, because the mean of its divisors is an integer number (1250502066).

Almost surely, 22501004131 is an apocalyptic number.

2501004131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2501004131 is an equidigital number, since it uses as much as digits as its factorization.

2501004131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 2501004131 is about 50010.0403019234. The cubic root of 2501004131 is about 1357.3904927000.

Adding to 2501004131 its reverse (1314001052), we get a palindrome (3815005183).

The spelling of 2501004131 in words is "two billion, five hundred one million, four thousand, one hundred thirty-one".