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250211142133 is a prime number
BaseRepresentation
bin1110100100000110111…
…1110000100111110101
3212220211122101222200021
43221001233300213311
513044413023022013
6310540113045141
724035315421331
oct3510157604765
9786748358607
10250211142133
1197128737487
12405ab2567b1
131a796a47874
14c1788947c1
156796624a8d
hex3a41bf09f5

250211142133 has 2 divisors, whose sum is σ = 250211142134. Its totient is φ = 250211142132.

The previous prime is 250211142131. The next prime is 250211142173. The reversal of 250211142133 is 331241112052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125342905444 + 124868236689 = 354038^2 + 353367^2 .

It is a cyclic number.

It is not a de Polignac number, because 250211142133 - 21 = 250211142131 is a prime.

Together with 250211142131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 250211142098 and 250211142107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250211142131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125105571066 + 125105571067.

It is an arithmetic number, because the mean of its divisors is an integer number (125105571067).

Almost surely, 2250211142133 is an apocalyptic number.

It is an amenable number.

250211142133 is a deficient number, since it is larger than the sum of its proper divisors (1).

250211142133 is an equidigital number, since it uses as much as digits as its factorization.

250211142133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 250211142133 its reverse (331241112052), we get a palindrome (581452254185).

The spelling of 250211142133 in words is "two hundred fifty billion, two hundred eleven million, one hundred forty-two thousand, one hundred thirty-three".