Base | Representation |
---|---|
bin | 10111010100001001… |
… | …001000011011111001 |
3 | 2101121122212222012200 |
4 | 113110021020123321 |
5 | 402232201000441 |
6 | 15300033300413 |
7 | 1544236330044 |
oct | 272411103371 |
9 | 71548788180 |
10 | 25034000121 |
11 | a6870498a9 |
12 | 4a27a04709 |
13 | 248c5ac130 |
14 | 12d6ab7c5b |
15 | 9b7b8b7b6 |
hex | 5d42486f9 |
25034000121 has 48 divisors (see below), whose sum is σ = 40764552192. Its totient is φ = 14698454400.
The previous prime is 25034000113. The next prime is 25034000141. The reversal of 25034000121 is 12100043052.
25034000121 is a `hidden beast` number, since 2 + 503 + 40 + 0 + 0 + 121 = 666.
It is not a de Polignac number, because 25034000121 - 23 = 25034000113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25034000094 and 25034000103.
It is not an unprimeable number, because it can be changed into a prime (25034000141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 208911 + ... + 306123.
It is an arithmetic number, because the mean of its divisors is an integer number (849261504).
Almost surely, 225034000121 is an apocalyptic number.
It is an amenable number.
25034000121 is a deficient number, since it is larger than the sum of its proper divisors (15730552071).
25034000121 is a wasteful number, since it uses less digits than its factorization.
25034000121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97334 (or 97331 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 18.
Adding to 25034000121 its reverse (12100043052), we get a palindrome (37134043173).
The spelling of 25034000121 in words is "twenty-five billion, thirty-four million, one hundred twenty-one", and thus it is an aban number.
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