251000117 has 2 divisors, whose sum is σ = 251000118. Its totient is φ = 251000116.

The previous prime is 251000111. The next prime is 251000153. The reversal of 251000117 is 711000152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 193376836 + 57623281 = 13906^2 + 7591^2 .

It is a cyclic number.

It is not a de Polignac number, because 251000117 - 2¹⁰ = 250999093 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 251000095 and 251000104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (251000111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125500058 + 125500059.

It is an arithmetic number, because the mean of its divisors is an integer number (125500059).

Almost surely, 2^251000117 is an apocalyptic number.

It is an amenable number.

251000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

251000117 is an equidigital number, since it uses as much as digits as its factorization.

251000117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70, while the sum is 17.

The square root of 251000117 is about 15842.9832102417. The cubic root of 251000117 is about 630.7994528790.

Adding to 251000117 its reverse (711000152), we get a palindrome (962000269).

The spelling of 251000117 in words is "two hundred fifty-one million, one hundred seventeen", and thus it is an aban number.