25100113 has 4 divisors (see below), whose sum is σ = 25402608. Its totient is φ = 24797620.

The previous prime is 25100087. The next prime is 25100123. The reversal of 25100113 is 31100152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-25100113 is a prime.

It is a super-2 number, since 2×25100113² = 1260031345225538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25100093 and 25100102.

It is not an unprimeable number, because it can be changed into a prime (25100123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151123 + ... + 151288.

It is an arithmetic number, because the mean of its divisors is an integer number (6350652).

Almost surely, 2^25100113 is an apocalyptic number.

It is an amenable number.

25100113 is a deficient number, since it is larger than the sum of its proper divisors (302495).

25100113 is an equidigital number, since it uses as much as digits as its factorization.

25100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 302494.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 25100113 is about 5010.0012974050. The cubic root of 25100113 is about 292.7915635602.

Subtracting from 25100113 its sum of digits (13), we obtain a square (25100100 = 5010²).

Adding to 25100113 its reverse (31100152), we get a palindrome (56200265).

The spelling of 25100113 in words is "twenty-five million, one hundred thousand, one hundred thirteen".