251041031 has 2 divisors, whose sum is σ = 251041032. Its totient is φ = 251041030.

The previous prime is 251041013. The next prime is 251041039. The reversal of 251041031 is 130140152.

Together with previous prime (251041013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-251041031 is a prime.

It is a super-4 number, since 4×251041031⁴ (a number of 35 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (251041039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125520515 + 125520516.

It is an arithmetic number, because the mean of its divisors is an integer number (125520516).

Almost surely, 2^251041031 is an apocalyptic number.

251041031 is a deficient number, since it is larger than the sum of its proper divisors (1).

251041031 is an equidigital number, since it uses as much as digits as its factorization.

251041031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 251041031 is about 15844.2743917164. The cubic root of 251041031 is about 630.8337252755.

Adding to 251041031 its reverse (130140152), we get a palindrome (381181183).

The spelling of 251041031 in words is "two hundred fifty-one million, forty-one thousand, thirty-one".