Base | Representation |
---|---|
bin | 1110100111011110001… |
… | …1111101110100100101 |
3 | 220000011120022221110012 |
4 | 3221313203331310211 |
5 | 13103240142121013 |
6 | 311205444540005 |
7 | 24066560644604 |
oct | 3516743756445 |
9 | 800146287405 |
10 | 251114020133 |
11 | 97551355049 |
12 | 408016b1605 |
13 | 1a8abb0b1c2 |
14 | c22275da3b |
15 | 67eaa1e1a8 |
hex | 3a778fdd25 |
251114020133 has 16 divisors (see below), whose sum is σ = 273123936000. Its totient is φ = 229910835456.
The previous prime is 251114020109. The next prime is 251114020139. The reversal of 251114020133 is 331020411152.
It is a cyclic number.
It is not a de Polignac number, because 251114020133 - 224 = 251097242917 is a prime.
It is a super-2 number, since 2×2511140201332 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 251114020099 and 251114020108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (251114020139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3501368 + ... + 3572366.
It is an arithmetic number, because the mean of its divisors is an integer number (17070246000).
Almost surely, 2251114020133 is an apocalyptic number.
It is an amenable number.
251114020133 is a deficient number, since it is larger than the sum of its proper divisors (22009915867).
251114020133 is a wasteful number, since it uses less digits than its factorization.
251114020133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76676.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 251114020133 its reverse (331020411152), we get a palindrome (582134431285).
The spelling of 251114020133 in words is "two hundred fifty-one billion, one hundred fourteen million, twenty thousand, one hundred thirty-three".
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