Base | Representation |
---|---|
bin | 10111011000111010… |
… | …011111111001001111 |
3 | 2101211020111221011201 |
4 | 113120322133321033 |
5 | 402413144101002 |
6 | 15312013130331 |
7 | 1546230622015 |
oct | 273072377117 |
9 | 71736457151 |
10 | 25114050127 |
11 | a718254631 |
12 | 4a4a7899a7 |
13 | 24a30591ba |
14 | 13035948b5 |
15 | 9bec00087 |
hex | 5d8e9fe4f |
25114050127 has 2 divisors, whose sum is σ = 25114050128. Its totient is φ = 25114050126.
The previous prime is 25114050113. The next prime is 25114050133. The reversal of 25114050127 is 72105041152.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25114050127 - 27 = 25114049999 is a prime.
It is a super-2 number, since 2×251140501272 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 25114050095 and 25114050104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25114050827) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12557025063 + 12557025064.
It is an arithmetic number, because the mean of its divisors is an integer number (12557025064).
Almost surely, 225114050127 is an apocalyptic number.
25114050127 is a deficient number, since it is larger than the sum of its proper divisors (1).
25114050127 is an equidigital number, since it uses as much as digits as its factorization.
25114050127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2800, while the sum is 28.
Adding to 25114050127 its reverse (72105041152), we get a palindrome (97219091279).
The spelling of 25114050127 in words is "twenty-five billion, one hundred fourteen million, fifty thousand, one hundred twenty-seven".
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