25114050131 has 4 divisors (see below), whose sum is σ = 25126017000. Its totient is φ = 25102083264.

The previous prime is 25114050127. The next prime is 25114050133. The reversal of 25114050131 is 13105041152.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25114050131 - 2² = 25114050127 is a prime.

It is a super-2 number, since 2×25114050131² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25114050097 and 25114050106.

It is not an unprimeable number, because it can be changed into a prime (25114050133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5980286 + ... + 5984483.

It is an arithmetic number, because the mean of its divisors is an integer number (6281504250).

Almost surely, 2^25114050131 is an apocalyptic number.

25114050131 is a deficient number, since it is larger than the sum of its proper divisors (11966869).

25114050131 is a wasteful number, since it uses less digits than its factorization.

25114050131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11966868.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 25114050131 its reverse (13105041152), we get a palindrome (38219091283).

The spelling of 25114050131 in words is "twenty-five billion, one hundred fourteen million, fifty thousand, one hundred thirty-one".