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2512499202949 is a prime number
BaseRepresentation
bin100100100011111100100…
…111110101101110000101
322220012012101111212021011
4210203330213311232011
5312131044243443244
65202120505322221
7346344033565351
oct44437447655605
98805171455234
102512499202949
118895aa33247a
12346b32a96371
13152c0a0b0008
1489869b1a461
15455510dd434
hex248fc9f5b85

2512499202949 has 2 divisors, whose sum is σ = 2512499202950. Its totient is φ = 2512499202948.

The previous prime is 2512499202911. The next prime is 2512499202977. The reversal of 2512499202949 is 9492029942152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2424305052324 + 88194150625 = 1557018^2 + 296975^2 .

It is a cyclic number.

It is not a de Polignac number, because 2512499202949 - 27 = 2512499202821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2512499202893 and 2512499202902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2512499202349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256249601474 + 1256249601475.

It is an arithmetic number, because the mean of its divisors is an integer number (1256249601475).

Almost surely, 22512499202949 is an apocalyptic number.

It is an amenable number.

2512499202949 is a deficient number, since it is larger than the sum of its proper divisors (1).

2512499202949 is an equidigital number, since it uses as much as digits as its factorization.

2512499202949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8398080, while the sum is 58.

The spelling of 2512499202949 in words is "two trillion, five hundred twelve billion, four hundred ninety-nine million, two hundred two thousand, nine hundred forty-nine".