Base | Representation |
---|---|
bin | 1110100111111111011… |
… | …0101010101100000001 |
3 | 220000112021002222100012 |
4 | 3221333312222230001 |
5 | 13104031300441400 |
6 | 311231334434305 |
7 | 24103200311543 |
oct | 3517766525401 |
9 | 800467088305 |
10 | 251253140225 |
11 | 9761293602a |
12 | 40840202995 |
13 | 1a90189ab99 |
14 | c237015693 |
15 | 6807d4ed35 |
hex | 3a7fdaab01 |
251253140225 has 24 divisors (see below), whose sum is σ = 325244808000. Its totient is φ = 192177465920.
The previous prime is 251253140219. The next prime is 251253140227. The reversal of 251253140225 is 522041352152.
It is not a de Polignac number, because 251253140225 - 234 = 234073271041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 251253140191 and 251253140200.
It is not an unprimeable number, because it can be changed into a prime (251253140227) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1207151 + ... + 1399899.
It is an arithmetic number, because the mean of its divisors is an integer number (13551867000).
Almost surely, 2251253140225 is an apocalyptic number.
251253140225 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
251253140225 is a deficient number, since it is larger than the sum of its proper divisors (73991667775).
251253140225 is a wasteful number, since it uses less digits than its factorization.
251253140225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195049 (or 195044 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 251253140225 its reverse (522041352152), we get a palindrome (773294492377).
The spelling of 251253140225 in words is "two hundred fifty-one billion, two hundred fifty-three million, one hundred forty thousand, two hundred twenty-five".
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