2512533313319 has 2 divisors, whose sum is σ = 2512533313320. Its totient is φ = 2512533313318.

The previous prime is 2512533313259. The next prime is 2512533313321. The reversal of 2512533313319 is 9133133352152.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2512533313319 is a prime.

It is a super-2 number, since 2×2512533313319² (a number of 26 digits) contains 22 as substring.

Together with 2512533313321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2512533313919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256266656659 + 1256266656660.

It is an arithmetic number, because the mean of its divisors is an integer number (1256266656660).

Almost surely, 2^{2512533313319} is an apocalyptic number.

2512533313319 is a deficient number, since it is larger than the sum of its proper divisors (1).

2512533313319 is an equidigital number, since it uses as much as digits as its factorization.

2512533313319 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 218700, while the sum is 41.

The spelling of 2512533313319 in words is "two trillion, five hundred twelve billion, five hundred thirty-three million, three hundred thirteen thousand, three hundred nineteen".