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25139953 = 83302891
BaseRepresentation
bin101111111100…
…1101011110001
31202022020112101
41133321223301
522413434303
62254500401
7423454216
oct137715361
952266471
1025139953
1113211023
128504701
135292b17
1434a5b0d
152318d1d
hex17f9af1

25139953 has 4 divisors (see below), whose sum is σ = 25442928. Its totient is φ = 24836980.

The previous prime is 25139927. The next prime is 25139969. The reversal of 25139953 is 35993152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25139953 - 29 = 25139441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25139053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151363 + ... + 151528.

It is an arithmetic number, because the mean of its divisors is an integer number (6360732).

Almost surely, 225139953 is an apocalyptic number.

It is an amenable number.

25139953 is a deficient number, since it is larger than the sum of its proper divisors (302975).

25139953 is an equidigital number, since it uses as much as digits as its factorization.

25139953 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 302974.

The product of its digits is 36450, while the sum is 37.

The square root of 25139953 is about 5013.9757677915. The cubic root of 25139953 is about 292.9463922084.

It can be divided in two parts, 251 and 39953, that added together give a palindrome (40204).

The spelling of 25139953 in words is "twenty-five million, one hundred thirty-nine thousand, nine hundred fifty-three".

Divisors: 1 83 302891 25139953