Base | Representation |
---|---|
bin | 111001001010110101100110… |
… | …100111111100010111100111 |
3 | 1012222020210120002221210211111 |
4 | 321022311212213330113213 |
5 | 230423441101432101210 |
6 | 2250430524351045451 |
7 | 103650315045635404 |
oct | 7112654647742747 |
9 | 1188223502853744 |
10 | 251433402222055 |
11 | 73129341776519 |
12 | 24249589810887 |
13 | aa3b0b67a4151 |
14 | 4613627a6b2ab |
15 | 1e1055e4cd88a |
hex | e4ad669fc5e7 |
251433402222055 has 4 divisors (see below), whose sum is σ = 301720082666472. Its totient is φ = 201146721777640.
The previous prime is 251433402222047. The next prime is 251433402222071. The reversal of 251433402222055 is 550222204334152.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 251433402222055 - 23 = 251433402222047 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 251433402221999 and 251433402222017.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25143340222201 + ... + 25143340222210.
It is an arithmetic number, because the mean of its divisors is an integer number (75430020666618).
Almost surely, 2251433402222055 is an apocalyptic number.
251433402222055 is a deficient number, since it is larger than the sum of its proper divisors (50286680444417).
251433402222055 is an equidigital number, since it uses as much as digits as its factorization.
251433402222055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50286680444416.
The product of its (nonzero) digits is 576000, while the sum is 40.
The spelling of 251433402222055 in words is "two hundred fifty-one trillion, four hundred thirty-three billion, four hundred two million, two hundred twenty-two thousand, fifty-five".
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