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251453132534055 = 35231271812283619
BaseRepresentation
bin111001001011000111111110…
…101001000111000100100111
31012222022200111011000111200210
4321023013332221013010213
5230424302003412042210
62250443550244110503
7103651614014551044
oct7113077651070447
91188280434014623
10251453132534055
1173136746a449a1
1224251375395433
13aa3cc0c334c8a
14461457a1d01cb
151e10d16726e20
hexe4b1fea47127

251453132534055 has 192 divisors, whose sum is σ = 427666890424320. Its totient is φ = 125913378286080.

The previous prime is 251453132534053. The next prime is 251453132534059. The reversal of 251453132534055 is 550435231354152.

It is not a de Polignac number, because 251453132534055 - 21 = 251453132534053 is a prime.

It is a super-2 number, since 2×2514531325340552 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 251453132533995 and 251453132534013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (251453132534053) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 406224769536 + ... + 406224770154.

It is an arithmetic number, because the mean of its divisors is an integer number (2227431720960).

Almost surely, 2251453132534055 is an apocalyptic number.

251453132534055 is a deficient number, since it is larger than the sum of its proper divisors (176213757890265).

251453132534055 is a wasteful number, since it uses less digits than its factorization.

251453132534055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1422 (or 1241 counting only the distinct ones).

The product of its (nonzero) digits is 5400000, while the sum is 48.

The spelling of 251453132534055 in words is "two hundred fifty-one trillion, four hundred fifty-three billion, one hundred thirty-two million, five hundred thirty-four thousand, fifty-five".