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25150213997 = 211119195327
BaseRepresentation
bin10111011011000100…
…011100111101101101
32101220202120020200022
4113123010130331231
5403001423321442
615315344211525
71550150202026
oct273304347555
971822506608
1025150213997
11a736705027
124a5a909ba5
1324aa6ab93c
1413082c9c4d
159c2e953d2
hex5db11cf6d

25150213997 has 4 divisors (see below), whose sum is σ = 25269409536. Its totient is φ = 25031018460.

The previous prime is 25150213961. The next prime is 25150214053. The reversal of 25150213997 is 79931205152.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25150213997 - 210 = 25150212973 is a prime.

It is a super-3 number, since 3×251502139973 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25150213927) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59597453 + ... + 59597874.

It is an arithmetic number, because the mean of its divisors is an integer number (6317352384).

Almost surely, 225150213997 is an apocalyptic number.

It is an amenable number.

25150213997 is a deficient number, since it is larger than the sum of its proper divisors (119195539).

25150213997 is a wasteful number, since it uses less digits than its factorization.

25150213997 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119195538.

The product of its (nonzero) digits is 170100, while the sum is 44.

The spelling of 25150213997 in words is "twenty-five billion, one hundred fifty million, two hundred thirteen thousand, nine hundred ninety-seven".

Divisors: 1 211 119195327 25150213997