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252113242445 = 550422648489
BaseRepresentation
bin1110101011001100011…
…1101100100101001101
3220002202012112200202222
43222303013230211031
513112311442224240
6311452541425125
724133413126311
oct3526307544515
9802665480688
10252113242445
1197a14397609
1240a4026b1a5
131aa0ab353cc
14c2b9347b41
1568585e9eb5
hex3ab31ec94d

252113242445 has 4 divisors (see below), whose sum is σ = 302535890940. Its totient is φ = 201690593952.

The previous prime is 252113242387. The next prime is 252113242487. The reversal of 252113242445 is 544242311252.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 166871433001 + 85241809444 = 408499^2 + 291962^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-252113242445 is a prime.

It is a super-2 number, since 2×2521132424452 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25211324240 + ... + 25211324249.

It is an arithmetic number, because the mean of its divisors is an integer number (75633972735).

Almost surely, 2252113242445 is an apocalyptic number.

It is an amenable number.

252113242445 is a deficient number, since it is larger than the sum of its proper divisors (50422648495).

252113242445 is an equidigital number, since it uses as much as digits as its factorization.

252113242445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50422648494.

The product of its digits is 76800, while the sum is 35.

Adding to 252113242445 its reverse (544242311252), we get a palindrome (796355553697).

The spelling of 252113242445 in words is "two hundred fifty-two billion, one hundred thirteen million, two hundred forty-two thousand, four hundred forty-five".

Divisors: 1 5 50422648489 252113242445