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252131031403 = 2087120810269
BaseRepresentation
bin1110101011010000101…
…1100011100101101011
3220002210110000110122021
43222310023203211223
513112331021001103
6311454415005311
724134020256206
oct3526413434553
9802713013567
10252131031403
1197a23437729
1240a46209837
131aa11723314
14c2bb85893d
156859e60bbd
hex3ab42e396b

252131031403 has 4 divisors (see below), whose sum is σ = 252251843760. Its totient is φ = 252010219048.

The previous prime is 252131031401. The next prime is 252131031407. The reversal of 252131031403 is 304130131252.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 252131031403 - 21 = 252131031401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (252131031401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60403048 + ... + 60407221.

It is an arithmetic number, because the mean of its divisors is an integer number (63062960940).

Almost surely, 2252131031403 is an apocalyptic number.

252131031403 is a deficient number, since it is larger than the sum of its proper divisors (120812357).

252131031403 is a wasteful number, since it uses less digits than its factorization.

252131031403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120812356.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 252131031403 its reverse (304130131252), we get a palindrome (556261162655).

The spelling of 252131031403 in words is "two hundred fifty-two billion, one hundred thirty-one million, thirty-one thousand, four hundred three".

Divisors: 1 2087 120810269 252131031403