Base | Representation |
---|---|
bin | 100100101100110110001… |
… | …000100010100010100101 |
3 | 22221002212021120101220111 |
4 | 210230312020202202211 |
5 | 312310131311323140 |
6 | 5210340550133021 |
7 | 350132564244622 |
oct | 44546610424245 |
9 | 8832767511814 |
10 | 2522054011045 |
11 | 892662815198 |
12 | 34895a951171 |
13 | 153aa079510a |
14 | 8a0d4ab3349 |
15 | 4590ed5c7ea |
hex | 24b362228a5 |
2522054011045 has 32 divisors (see below), whose sum is σ = 3057912000000. Its totient is φ = 1996769087040.
The previous prime is 2522054011021. The next prime is 2522054011073. The reversal of 2522054011045 is 5401104502252.
It is not a de Polignac number, because 2522054011045 - 217 = 2522053879973 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2522054010998 and 2522054011016.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 764488806 + ... + 764492104.
It is an arithmetic number, because the mean of its divisors is an integer number (95559750000).
Almost surely, 22522054011045 is an apocalyptic number.
It is an amenable number.
2522054011045 is a deficient number, since it is larger than the sum of its proper divisors (535857988955).
2522054011045 is a wasteful number, since it uses less digits than its factorization.
2522054011045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6273.
The product of its (nonzero) digits is 16000, while the sum is 31.
Adding to 2522054011045 its reverse (5401104502252), we get a palindrome (7923158513297).
The spelling of 2522054011045 in words is "two trillion, five hundred twenty-two billion, fifty-four million, eleven thousand, forty-five".
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